SOURCE CODE METODE SECANT C++

#include<iostream>
#include<conio.h>
#include<math.h>

using namespace std;

float f(float x)
{
 float y;
 y=(x*x)-(5*x)-6;
 return y;
}
 main()
{
 int n=0;
 float x[20],tol,er;
 cout<<"\t\t\t\tMETODE SECANT\n";
 cout<<"\t\t\t\t=============\n\n";
 cout<<"\t\t\t\tFAJAR NUGRAHA WAHYU\n";
 cout<<"\t\t\t\t   11140910000013\n\n";
 cout<<"\t\t\t\t2x^2+2x-3\n";
 cout<<"\t\t\t\t=========\n\n";
 cout<<"Batas Awal \t= ";
 cin>>x[0];
 cout<<"Batas AKhir \t= ";
 cin>>x[1];
 cout<<"toleransi \t= ";
 cin>>tol;
     cout<<"iterasi\t "<<"x(n-1)  "<<"  x(n) "<<"    x(n+1)  "<<"   f n+1     "<<"   eror\t\n\n\n";
 do
 {
  n++;
  x[n+1]=((x[n]*f(x[n-1]))-(x[n-1]*f(x[n])))/(f(x[n-1])-f(x[n]));
  er=((6-x[n-1])/6)*100;
  cout<<n<<"\t"<<x[n-1]<<"  "<<x[n]<<"  "<<x[n+1]<<"  "<<f(x[n+1])<<"  "<< fabs(er)<<" \n";
 }
 while(fabs(f(x[n+1]))>tol);
 cout<<endl;
 cout<<"akarnya adalah ="<<x[n+1];
 cout<<endl;

}


Lazada Indonesia
MAU DOWNLOAD? KLIK DIBAWAH
KLIK DOWNLOAD
http://pastebin.com/8Mj49CX3 Lazada Indonesia

1 Response to "SOURCE CODE METODE SECANT C++"

  1. Terimakasih gan sangat membantu kita dalam mengerjakan tugas metode numerik

    ReplyDelete